document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=502826>Question 502826</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if cos^-1(-2/7)=x, find the exact value for each: sinx,cosx, tanx, cotx, secx,& cscx? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #339043 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=339043\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if cos^-1(-2/7)=x, find the exact value for each: sinx,cosx, tanx, cotx, secx,& cscx?<BR>\n" );
document.write( "**<BR>\n" );
document.write( "cos^-1(-2/7) is an inverse cos function which says cos of angle x=-2/7, which means you are working with a reference angle x in quadrant II where cos is negative. <BR>\n" );
document.write( "sin x=&#8730;45/7<BR>\n" );
document.write( "cos x=-2/7 (given)<BR>\n" );
document.write( "tan x=-&#8730;45/2<BR>\n" );
document.write( "csc x=7&#8730;45/45<BR>\n" );
document.write( "sec x=-7/2<BR>\n" );
document.write( "cot x=-2&#8730;45/45 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );