document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=502953>Question 502953</A>: <I><SPAN STYLE=\"word-break: break-all;\"> * Please help me. I couldn't figure out how to write the linear equation of this problem. thank you.\r<BR>\n" );
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document.write( "John’s father is 5 times older than John and John is twice as old as his sister<BR>\n" );
document.write( "Alice. In two years time, the sum of their ages will be 60 . How old is John<BR>\n" );
document.write( "now?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #339023 by </B><A HREF=/tutors/aboutme.mpl?userid=jrb1965><B>jrb1965(16)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jrb1965><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=339023\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> F = Father<BR>\n" );
document.write( "J = John<BR>\n" );
document.write( "A = Alice\r<BR>\n" );
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document.write( "Now J = 2A, and F = 5J = 5(2A) = 10A\r<BR>\n" );
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document.write( "In two years (F + 2) + (J + 2) + (A + 2) = 60, so F + J + A = 54\r<BR>\n" );
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document.write( "Substitute all in terms of A\r<BR>\n" );
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document.write( "10A + 2A + A = 54, 13A = 54, so A = 54/13 (check your numbers, they usually make these come out in even years)\r<BR>\n" );
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document.write( "F = 41.54<BR>\n" );
document.write( "J = 8.31<BR>\n" );
document.write( "A = 4.15 </SPAN>\n" );
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