document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=502951>Question 502951</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the measurement of the largest angle in a triangle is twice the measurement of the smallest angle. the third angle 10 degrees less than the largest angle. find the measure of each angle.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #339022 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=339022\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> smallest angle =x<BR>\n" );
document.write( "largest angle =2x<BR>\n" );
document.write( "third angle = 2x-10\r<BR>\n" );
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document.write( "The sum of the angles of triangle = 180 deg\r<BR>\n" );
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document.write( "x+2x+2x-10=180<BR>\n" );
document.write( "5x-10=180<BR>\n" );
document.write( "5x=180+10<BR>\n" );
document.write( "5x=190<BR>\n" );
document.write( "x=38 deg<BR>\n" );
document.write( "plug x <BR>\n" );
document.write( "2x=>2*38=76 deg<BR>\n" );
document.write( "2x-10=> 76-10 = 66 deg<BR>\n" );
document.write( "***\r<BR>\n" );
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document.write( "66+76+38=180 deg </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );