document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=50863>Question 50863</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please can you help me find x\r<BR>\n" );
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document.write( "((( 8x³/2x – 3x – 2 = 0 ))) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #33902 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=33902\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 8x³/2x – 3x – 2 = 0<BR>\n" );
document.write( "If the 2x is the denominator of the 8x^3 you get:<BR>\n" );
document.write( "4x^2-4x-2=0<BR>\n" );
document.write( "Using the quadratic formula you get:<BR>\n" );
document.write( "x=[4+-sqrt(16-4*4*(-2)]/8<BR>\n" );
document.write( "x=[4+-sqrt(48)]/8<BR>\n" );
document.write( "x=[4+-4sqrt3]/8<BR>\n" );
document.write( "x=[1+-sqrt3]/2<BR>\n" );
document.write( "x=(1/2)+(1/2)sqrt3 or x=(1/2)-(1/2)sqrt3\r<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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