document.write( "Question 502940: a man drove 5 hours. On the return trip his speed was 9 mph less and the trip took 6 hrs. What was his speed each way? \n" ); document.write( "
Algebra.Com's Answer #339019 by jrb1965(16)\"\" \"About 
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Distance = Rate * Time
\n" ); document.write( "D1 = D2
\n" ); document.write( "D1 = S1 * T1
\n" ); document.write( "D2 = S2 * T2
\n" ); document.write( " so S1 * T1 = S2 * T2
\n" ); document.write( "S2 = S1 - 9
\n" ); document.write( "T1 = 5
\n" ); document.write( "T2 = 6\r
\n" ); document.write( "\n" ); document.write( " so S1 * 5 = (S1 - 9) * 6
\n" ); document.write( " 5S1 = 6S1 - 54
\n" ); document.write( "combine the S1 terms
\n" ); document.write( "S1 = 54 MPH
\n" ); document.write( "S2 = 45 MPH
\n" ); document.write( "D1 = D2 = 270 Miles
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