document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=502927>Question 502927</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this:  During the first part of a trip, a canoeist travels 36 miles at a certain speed. The canoeist travels 8 miles on the second part of the trip at a speed 5 mph slower. The total time for the trip is 5 hours. What was the speed on each part of the trip?\r<BR>\n" );
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document.write( "I have tried example problems that are similar but I seem to not understand this process. Thanks in advance for helping.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #339017 by </B><A HREF=/tutors/aboutme.mpl?userid=jrb1965><B>jrb1965(16)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jrb1965><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=339017\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Distance = Rate * Time<BR>\n" );
document.write( "Let S1  be the speed on part 1, and S2 be the speed on part 2<BR>\n" );
document.write( "Given S2 = S1 - 5<BR>\n" );
document.write( "Given T1 + T2 = 5, so T2 = 5 - T1<BR>\n" );
document.write( "36 = S1 * T1, so T1 = 36/S1<BR>\n" );
document.write( "8 = S2 * T2\r<BR>\n" );
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document.write( "Substituting the first 3 equations in the form of S1 into the 4th equation\r<BR>\n" );
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document.write( "8 = (S1 - 5) * (5 - (36/S1)) = 5S1 - 36 - 25 + (180/S1)\r<BR>\n" );
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document.write( "Multiply all terms by S1 to get the quadratic equation\r<BR>\n" );
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document.write( "5<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=S1%5E2 ALIGN=MIDDLE  ALT=\"S1%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > - 69<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=S1 ALIGN=MIDDLE  ALT=\"S1\"   DISABLED_style= \"max-width:90%; height:auto;\" > + 180 = 0\r<BR>\n" );
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document.write( "Use the quadratic formula <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=S1+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+ ALIGN=MIDDLE  ALT=\"S1+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "a = 5, b = -69, c = 180<BR>\n" );
document.write( "so S1 = 10.3 MPH (if you use the other solution, S2 would be negative)<BR>\n" );
document.write( "S2 = 5.3 MPH<BR>\n" );
document.write( "T1 = 3.5 Hours<BR>\n" );
document.write( "T2 = 1.5 Hours </SPAN>\n" );
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