document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=502181>Question 502181</A>: <I><SPAN STYLE=\"word-break: break-all;\"> (5a-4)= a+41/a-1\r<BR>\n" );
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document.write( "Please help if you can. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #339007 by </B><A HREF=/tutors/aboutme.mpl?userid=persian52><B>persian52(161)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=persian52><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=persian52><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=339007\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (5a-4)=a+(41)/(a)-1\r<BR>\n" );
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document.write( "Since a is on the right-hand side of the equation, switch the sides so it is on the left-hand side of the equation.<BR>\n" );
document.write( "a+(41)/(a)-1=(5a-4)\r<BR>\n" );
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document.write( "Find the LCD (least common denominator) of a+(41)/(a)-1+(5a-4).<BR>\n" );
document.write( "Least common denominator: a\r<BR>\n" );
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document.write( "Multiply each term in the equation by a in order to remove all the denominators from the equation.<BR>\n" );
document.write( "a*a+(41)/(a)*a-1*a=(5a-4)*a\r<BR>\n" );
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document.write( "Simplify the left-hand side of the equation by canceling the common terms.<BR>\n" );
document.write( "a^(2)-a+41=(5a-4)*a\r<BR>\n" );
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document.write( "Simplify the right-hand side of the equation by multiplying out all the terms.<BR>\n" );
document.write( "a^(2)-a+41=5a^(2)-4a\r<BR>\n" );
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document.write( "Move all terms not containing a to the right-hand side of the equation.<BR>\n" );
document.write( "a^(2)-a+41-5a^(2)+4a=0\r<BR>\n" );
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document.write( "Since a^(2) and -5a^(2) are like terms, add -5a^(2) to a^(2) to get -4a^(2).<BR>\n" );
document.write( "-4a^(2)-a+41+4a=0\r<BR>\n" );
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document.write( "Since -a and 4a are like terms, subtract 4a from -a to get 3a.<BR>\n" );
document.write( "-4a^(2)+3a+41=0\r<BR>\n" );
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document.write( "Multiply each term in the equation by -1.<BR>\n" );
document.write( "-4a^(2)*-1+3a*-1+41*-1=0*-1\r<BR>\n" );
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document.write( "Simplify the left-hand side of the equation by multiplying out all the terms.<BR>\n" );
document.write( "4a^(2)-3a-41=0*-1\r<BR>\n" );
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document.write( "Multiply 0 by -1 to get 0.<BR>\n" );
document.write( "4a^(2)-3a-41=0\r<BR>\n" );
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document.write( "Use the quadratic formula to find the solutions.  In this case, the values are a=4, b=-3, and c=-41.<BR>\n" );
document.write( "a=(-b\~(b^(2)-4ac))/(2a) where aa^(2)+ba+c=0\r<BR>\n" );
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document.write( "Substitute in the values of a=4, b=-3, and c=-41.<BR>\n" );
document.write( "a=(-(-3)\~((-3)^(2)-4(4)(-41)))/(2(4))\r<BR>\n" );
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document.write( "Multiply -1 by the -3 inside the parentheses.<BR>\n" );
document.write( "a=(3\~((-3)^(2)-4(4)(-41)))/(2(4))\r<BR>\n" );
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document.write( "Simplify the section inside the radical.<BR>\n" );
document.write( "a=(3\~(665))/(2(4))\r<BR>\n" );
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document.write( "Simplify the denominator of the quadratic formula.<BR>\n" );
document.write( "a=(3\~(665))/(8)\r<BR>\n" );
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document.write( "First, solve the + portion of \.<BR>\n" );
document.write( "a=(3+~(665))/(8)\r<BR>\n" );
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document.write( "Next, solve the - portion of \.<BR>\n" );
document.write( "a=(3-~(665))/(8)\r<BR>\n" );
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document.write( "The final answer is the combination of both solutions.<BR>\n" );
document.write( "a=(3+~(665))/(8),(3-~(665))/(8)_a<Z>APPR<z>3.6,-2.85 </SPAN>\n" );
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