document.write( "Question 502861: Factor the four term polynomial by grouping
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Algebra.Com's Answer #338969 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
I'll do the first one to get you started.\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E3%2B3x%5E2%2B9x%2B27\" Start with the given expression\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%5E3%2B3x%5E2%29%2B%289x%2B27%29\" Group the terms in two pairs\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%28x%2B3%29%2B9%28x%2B3%29\" Factor out the GCF \"x%5E2\" out of the first group. Factor out the GCF \"9\" out of the second group\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%5E2%2B9%29%28x%2B3%29\" Since we have the common term \"x%2B3\", we can combine like terms\r
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\n" ); document.write( "\n" ); document.write( "So \"x%5E3%2B3x%5E2%2B9x%2B27\" factors to \"%28x%5E2%2B9%29%28x%2B3%29\"\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"x%5E3%2B3x%5E2%2B9x%2B27=%28x%5E2%2B9%29%28x%2B3%29\"
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