document.write( "Question 502833: 2 planes leave airport same time. 1 travels 40mph faster than the other. If they are 2000 miles apart after 5 hours find there average speeds? \n" ); document.write( "
Algebra.Com's Answer #338957 by mananth(16946)\"\" \"About 
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Plane I x mph
\n" ); document.write( "Plane II x+ 40
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\n" ); document.write( "They are going away from each other.
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\n" ); document.write( "So add up their speed.
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\n" ); document.write( "combined speed = x+ 1 x + 40
\n" ); document.write( "( 2 x + 40 )
\n" ); document.write( "Time = 5 hours
\n" ); document.write( "Distance = 2000 miles
\n" ); document.write( "Distance = speed * time
\n" ); document.write( "( 2 x 40 )* 5 = 2000
\n" ); document.write( "10 x + 200 = 2000
\n" ); document.write( "10 x = 2000 + -200
\n" ); document.write( "10 x = 1800
\n" ); document.write( "/ 10
\n" ); document.write( "x= 180 mph Plane I
\n" ); document.write( "Plane II 180 + 40 = 220 mph
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