document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=502198>Question 502198</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the exact value of sec[sin^-1(-3/4)] </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #338938 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=338938\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the exact value of sec[sin^-1(-3/4)]<BR>\n" );
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document.write( "sin^-1(-3/4)=sin inverse<BR>\n" );
document.write( "Given problem asks to find the sec of an angle whose sine is (-3/4) in quadrant IV<BR>\n" );
document.write( "The cos of this same angle is then=4/5 (working with a 3-4-5 right triangle in quad IV)<BR>\n" );
document.write( "sec[sin^-1(-3/4)]=1/cos=5/4 </SPAN>\n" );
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