document.write( "Question 502383: Find the exact value of csc 9π/2 using periodic properties??
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document.write( "helpppppp pleaseee!! \n" );
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Algebra.Com's Answer #338930 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Find the exact value of csc 9π/2 using periodic properties? \n" ); document.write( "** \n" ); document.write( "9π/2=(4-1/2)π \n" ); document.write( "This means rotating counter-clockwise 4π times and another (1/2)π, which makes a reference π/2 where sin=1. \n" ); document.write( "Therefore, csc 9π/2=1/sin=1/1=1 \n" ); document.write( " |