document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=502387>Question 502387</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the exact value of tan 19&#960;/6 using periodic properties. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #338916 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=338916\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the exact value of tan 19&#960;/6 using periodic properties.<BR>\n" );
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document.write( "19&#960;/6=(3-1/6)&#960;<BR>\n" );
document.write( "This means going counter-clockwise 3&#960; and another (1/6)&#960; which places a reference angle of &#960;/6 in quadrant III where tan is positive.<BR>\n" );
document.write( "tan 19&#960;/6=&#8730;3/3 </SPAN>\n" );
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