document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=502514>Question 502514</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A coffee merchant combines coffee costing $5.00 per pound with coffee costing $3.50 per pound. How many pounds of each should be used to make 30 lb of a blend costing $4.20 per pound? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #338871 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=338871\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Here's a similar problem:<BR>\n" );
document.write( "-------------<BR>\n" );
document.write( "how many liters of a 70% acid solution must be mixed with a 15% acid solution to get 385L of a 60% acid solution?<BR>\n" );
document.write( "-------------------<BR>\n" );
document.write( "s = amount of 70%<BR>\n" );
document.write( "f = amount of 15%<BR>\n" );
document.write( "-------<BR>\n" );
document.write( "s + f = 385 (total solution)<BR>\n" );
document.write( "0.7s + 0.15f = 0.6*385 (total acid)<BR>\n" );
document.write( "-------<BR>\n" );
document.write( "f = 385 - s<BR>\n" );
document.write( "Sub for f in 2nd equation<BR>\n" );
document.write( "0.7s + 0.15(385-s) = 231<BR>\n" );
document.write( "70s + 5775 - 15s = 23100<BR>\n" );
document.write( "55s = 17325<BR>\n" );
document.write( "s = 315 liters of 70%<BR>\n" );
document.write( "------------<BR>\n" );
document.write( "f = 70 liters of 15%<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );