document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=501872>Question 501872</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given that m<LKN = 145°<BR>\n" );
document.write( "Angle LKM = (2x+10) Angle MKN = 4x-3<BR>\n" );
document.write( "May you please explain how to do this as i am having a hard time! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #338843 by </B><A HREF=/tutors/aboutme.mpl?userid=cleomenius><B>cleomenius(959)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=cleomenius><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=cleomenius><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=338843\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> It sounds as if angles LKM and MRN = LKN, which is 145 degrees.<BR>\n" );
document.write( "2x + 10 + 4x - 3 = 145<BR>\n" );
document.write( "6x + 7 = 145<BR>\n" );
document.write( "6x = 138<BR>\n" );
document.write( "x = 23<BR>\n" );
document.write( "LKM = 2(23) + 10 = 56 degrees<BR>\n" );
document.write( "MKN = 4(23) - 3 =  89 degrees<BR>\n" );
document.write( "56 degrees + 89 degrees = 145 degrees.<BR>\n" );
document.write( "This does check.<BR>\n" );
document.write( "Cleomenius.<BR>\n" );
document.write( " </SPAN>\n" );
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