document.write( "Question 50826: The length of a rectangle is 1 cm longer than its width. If the diagonal of the rectangle is 4 cm, what are the dimensions (the length and the width) of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #33883 by darq(90)\"\" \"About 
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The length of a rectangle is 1 cm longer than its width. If the diagonal of the rectangle is 4 cm, what are the dimensions (the length and the width) of the rectangle?\r
\n" ); document.write( "\n" ); document.write( "so we will have to right triangles:
\n" ); document.write( "edges will have x and x+1 lenght\r
\n" ); document.write( "\n" ); document.write( "and their squares' sum will equal to the square of 4.\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2Bx%5E2%2B2x%2B1=16\"
\n" ); document.write( "\"2x%5E2%2B2x%2B1=16\"
\n" ); document.write( "\"x%5E2%2Bx%2B%281%2F2%29=8\"
\n" ); document.write( "\"x%5E2%2Bx%2B%281%2F4%29=8-%281%2F4%29\"
\n" ); document.write( "\"%28x%2B%281%2F2%29%29%5E2=+%2831%2F4%29\"
\n" ); document.write( "\"x%2B%281%2F2%29=+sqrt%2831%29%2F2\"
\n" ); document.write( "\"x+=+%28sqrt%2831%29-1%29%2F2\"\r
\n" ); document.write( "\n" ); document.write( "this was the short edge\r
\n" ); document.write( "\n" ); document.write( "\"y=x%2B1\"
\n" ); document.write( "\"y+=++%28sqrt%2831%29%2B1%29%2F2\"\r
\n" ); document.write( "\n" ); document.write( "this is the long one
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