document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=502373>Question 502373</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Simplify the following quotient of complex numbers into the form a + bi. <BR>\n" );
document.write( "-7+6i/9+6i<BR>\n" );
document.write( "how do u form a bi i dont understand  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #338824 by </B><A HREF=/tutors/aboutme.mpl?userid=geetha_rama><B>geetha_rama(94)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=geetha_rama><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=338824\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> To express the above in the form of a+bi , multiply and divide the expression by the conjugate of the denominator (9-6i).<BR>\n" );
document.write( "(-7+6i)/(9+6i)<BR>\n" );
document.write( "=((-7+6i) * (9-6i))/(9+6i)(9-6i)<BR>\n" );
document.write( "= (-63+54i + 42i -36i^2)/81 -36i^2<BR>\n" );
document.write( "= (-63 +96i+ 36)/81+36  (since i^2 = -1)<BR>\n" );
document.write( "= (-27 + 96i)/117 <BR>\n" );
document.write( "= (-9 + 32i)/39  (divinding by 3)<BR>\n" );
document.write( "= -9/39 + 32i/39<BR>\n" );
document.write( "= -3/13 + 32i/39\r<BR>\n" );
document.write( "\n" );
document.write( "This in the form of a+bi where a = -3/13 and b = 32/39 </SPAN>\n" );
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