document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=502307>Question 502307</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Joe and Gayne lives 3 miles apart. They both leave their houses at the same time and walk to meet each other. Joe walks at 2.5mi/h and Gayne walks at 3.5mi/h. How far will be Joe walk before he meets Gayna?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #338814 by </B><A HREF=/tutors/aboutme.mpl?userid=geetha_rama><B>geetha_rama(94)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=geetha_rama><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=338814\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let at time t joe and gayna meet<BR>\n" );
document.write( "Distance covered by joe in time t is <BR>\n" );
document.write( "   d = 2.5*t -> eauaion 1<BR>\n" );
document.write( "Distance covered by Gayna in time t<BR>\n" );
document.write( "  3-d = 3.5*t\r<BR>\n" );
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document.write( "from equation 1,<BR>\n" );
document.write( "=>3 - 2.5t = 3.5t<BR>\n" );
document.write( "3 = 6t\r<BR>\n" );
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document.write( "t = 1/2 hr\r<BR>\n" );
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document.write( "Distance travelled by joe in 1/2 hr is 2.5*1/2 = 1.25 miles<BR>\n" );
document.write( "Jpe would haved walked 1.25 miles  before meeting Gayna </SPAN>\n" );
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