document.write( "Question 501771: may is 6 years younger than faye . Four years from now the product of thier ages is 352 find thier present ages \n" ); document.write( "
Algebra.Com's Answer #338808 by Maths68(1474)\"\" \"About 
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Let
\n" ); document.write( "Present age of May = m
\n" ); document.write( "Present age of Faye = f
\n" ); document.write( "May is 6 years younger than Faye means if we subtract 6 from the Faye's age both Faye and May will be of equal age
\n" ); document.write( "m=f-6.......................(1)
\n" ); document.write( "Four years from now means we have to add 4 in present age of May and Faye
\n" ); document.write( "f+4=m+4
\n" ); document.write( "then the product of thier ages is 352
\n" ); document.write( "(f+4)(m+4)=352
\n" ); document.write( "fm+4f+4m+16=352
\n" ); document.write( "fm+4f+4m=352-16
\n" ); document.write( "fm+4f+4m=336 .................(2)
\n" ); document.write( "Put the value of m from (1) to (2)
\n" ); document.write( "f(f-6)+4f+4(f-6)=336
\n" ); document.write( "f^2-6f+4f+4f-24=336
\n" ); document.write( "f^2-6f+8f=336+24
\n" ); document.write( "f^2+2f=360
\n" ); document.write( "f^2+2f-360=0
\n" ); document.write( "Now solve for f
\n" ); document.write( "f^2-18f+20f-360=0
\n" ); document.write( "f(f-18)+20(f-18)=0
\n" ); document.write( "(f-18)(f+20)=0
\n" ); document.write( "f-18= o or f+20=0
\n" ); document.write( "f=18 or f=-20(Impossible)
\n" ); document.write( "so
\n" ); document.write( "f=18
\n" ); document.write( "Put the value of f in (1)
\n" ); document.write( "m=f-6
\n" ); document.write( "m=18-6
\n" ); document.write( "m=12\r
\n" ); document.write( "\n" ); document.write( "May is 12 and Faye is 18 years old
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