document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=502219>Question 502219</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please help me solve this word problem: Jack is six years more than five times as old as Jill. if the sum of their ages is 78. how old is each? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #338786 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=338786\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let Ja be Jack's present age and Ji be Jill's present age.<BR>\n" );
document.write( "1) Ja + Ji = 78 \"...the sum of their ages is 78.\"<BR>\n" );
document.write( "2) Ja = 5Ji+6 \"Jack is six years more than five times as old as Jill.\" Rewrite equation 1) as:<BR>\n" );
document.write( "1a) Ja = 78-Ji and substitute for Ja in equation 2) to get:<BR>\n" );
document.write( "2a) 78-Ji =5Ji+6 Solve for Ji. Add Ji to both sides<BR>\n" );
document.write( "2b) 78 = 6Ji+6 Now subtract 6 from both sides.<BR>\n" );
document.write( "2c) 72 = 6Ji Finally, divide both sides by 6.<BR>\n" );
document.write( "2d) 12 = Ji Jill is 12 years old.<BR>\n" );
document.write( "1b) Ja = 78=Ji<BR>\n" );
document.write( "1c) Ja = 78-12<BR>\n" );
document.write( "1d) Ja = 66 Jack is 66 years old.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );