document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=502209>Question 502209</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello,<BR>\n" );
document.write( "I am having trouble getting started on an equation:\r<BR>\n" );
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document.write( "a two day marathon walk. total distance of the marathon is 26.2 miles.  On the first day, Martha starts walking at 10:00am.  she walks 4 miles per hour.  Carol stars two hours later than Marhta but decides to run to catch up to Martha.  Carol runs at a speed of 6 miles per hour.<BR>\n" );
document.write( "a. write an equation to represent the distance Martha travels.\r<BR>\n" );
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document.write( "b. write and equation to represent the distance Carol travels.<BR>\n" );
document.write( "c. solve the system of equations to find when Carol will catch up to Martha.<BR>\n" );
document.write( "d.  Carol wants to reduce the time she takes to catch up to Martha by 1 hour.  How can she do this by changing her starting time? How can she do this by changing her speed?\r<BR>\n" );
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document.write( "I am so confused on how to find a starting point to solve this problem.  Can you help me write a systems of equations please?  Thank you so much   EG><BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #338782 by </B><A HREF=/tutors/aboutme.mpl?userid=oberobic><B>oberobic(2304)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oberobic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=338782\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> d = r*t is the basic distance equation.<BR>\n" );
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document.write( "M = Martha's distance.<BR>\n" );
document.write( "M = 4 * t<BR>\n" );
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document.write( "C = Carol's distance<BR>\n" );
document.write( "C = 6 * t<BR>\n" );
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document.write( "However, their times are different by 2 hr.<BR>\n" );
document.write( "If M's time = t, then C's time = t-2.<BR>\n" );
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document.write( "When C catches up, the two have gone the same distance.<BR>\n" );
document.write( "M = C<BR>\n" );
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document.write( "4*t = 6*(t-2)<BR>\n" );
document.write( "4t = 6t -12<BR>\n" );
document.write( "-2t = -12<BR>\n" );
document.write( "t = 6<BR>\n" );
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document.write( "So Carol catches up at the 24 mile post.<BR>\n" );
document.write( "That would be 4 pm<BR>\n" );
document.write( "Carol ran for 4 hours at 6 mph.<BR>\n" );
document.write( "Martha walked for 6 hr at 4 mph<BR>\n" );
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document.write( "Carol can catch up an earlier by leaving earlier or by running faster.<BR>\n" );
document.write( "Leaving earlier is likely easier.<BR>\n" );
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document.write( "Done. </SPAN>\n" );
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