document.write( "Question 502089: The sum of Victor’s and Ellen’s age is 40 years. Victor’s age 10 years from now will be 1 year less than 4 times Ellen’s age 6 years ago. Find their present ages. \n" ); document.write( "
Algebra.Com's Answer #338771 by oberobic(2304)\"\" \"About 
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V +E = 40
\n" ); document.write( "V+10 = Victor's age 10 years from now.
\n" ); document.write( "E+10 = Ellen's age 10 years from now.
\n" ); document.write( "E-6 = Ellen's age 6 years ago.
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\n" ); document.write( "(V+10) +1 = 4*(E-6)
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\n" ); document.write( "Substitute for V
\n" ); document.write( "V = 40-E
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\n" ); document.write( "40-E + 10 +1 = 4E -24
\n" ); document.write( "51 -E = 4E - 24
\n" ); document.write( "75 -E = 4E
\n" ); document.write( "75 = 5E
\n" ); document.write( "E = 15
\n" ); document.write( ".
\n" ); document.write( "V+E = 40
\n" ); document.write( "V+15 = 40
\n" ); document.write( "V = 25
\n" ); document.write( ".
\n" ); document.write( "Always check your work
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\n" ); document.write( "In 10 years, V = 35
\n" ); document.write( "Six years ago, E = 9
\n" ); document.write( "4*E = 36
\n" ); document.write( "which is 1 more than V+10.
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\n" ); document.write( "Answer: Victor's current age is 25; Ellen's is 15.
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\n" ); document.write( "Done. \n" ); document.write( "
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