document.write( "Question 501818: 2(y)^1/9 - 3 (y)^1/18 + 1 = 0\r
\n" ); document.write( "\n" ); document.write( "I've got it broken down to
\n" ); document.write( "(2y^1/18 -1)(y^1/18 - 1) = 0\r
\n" ); document.write( "\n" ); document.write( "I'm confused as to what the next step is and how to get there!\r
\n" ); document.write( "\n" ); document.write( "Thanks so much,
\n" ); document.write( "Tracy \n" ); document.write( "
Algebra.Com's Answer #338682 by htmentor(1343)\"\" \"About 
You can put this solution on YOUR website!
2(y)^1/9 - 3 (y)^1/18 + 1 = 0\r
\n" ); document.write( "\n" ); document.write( "I've got it broken down to
\n" ); document.write( "(2y^1/18 -1)(y^1/18 - 1) = 0
\n" ); document.write( "========================================
\n" ); document.write( "To avoid working with fractional exponents, let x = y^(1/18)
\n" ); document.write( "Then we can rewrite the equation as:
\n" ); document.write( "\"2x%5E2+-+3x+%2B+1+=+0\"
\n" ); document.write( "This can be factored as:
\n" ); document.write( "(2x-1)(x-1) = 0
\n" ); document.write( "The solutions are x = 1/2, x = 1
\n" ); document.write( "Therefore 1 = y^(1/18) -> y = 1
\n" ); document.write( "For the other root, 1/2 = y^(1/18)
\n" ); document.write( "To solve for y raise both sides to the 18th power:
\n" ); document.write( "(1/2)^18 = y
\n" ); document.write( "So the two roots are 1 and (1/2)^18\r
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