document.write( "Question 50825This question is from textbook Saxon Algebra 1
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document.write( ": I think I'm just confused by the terminology. Saxon asks to solve the following by \"elimination\" to solve equivalent fractions, but with only positive numbers on the variable side, I can't get the problem to work out as in their examples - each of which has at least one negative number.\r
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document.write( "a. 4y + 3x = -7 and 3y + 2x = -6\r
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document.write( "They say to multiply each equation by one of the variable terms from the other...i.e. multiply first one by 2x and the other by 3x....doesn't work out. ?????? I end up with a plus 6x in both rather than a +6x and a -6x which would cancel out each other, leaving room to solve for y.\r
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document.write( "I'm missing something......:-(\r
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document.write( "Rebecca \n" );
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Algebra.Com's Answer #33868 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 1st: 4y + 3x = -7 \n" ); document.write( "2nd: 3y + 2x = -6 \n" ); document.write( "------------------ \n" ); document.write( "You can choose which variable you want to eliminate. \n" ); document.write( "If you want to eliminate the y-terms, mutiply 1st \n" ); document.write( "thru by 3 and 2nd thru by 4 to get: \n" ); document.write( "3rd: 12y+9x=-21 \n" ); document.write( "4th: 12y+8x=-24 \n" ); document.write( "Now subtract 4th from 3rd to get:\r \n" ); document.write( "\n" ); document.write( "x=-3 \n" ); document.write( "Substitute that into 1st or 2nd: it doesn't matter which: \n" ); document.write( "4y+3(-3)=-7 \n" ); document.write( "4y=2 \n" ); document.write( "y=1/2 \n" ); document.write( "Solution: \n" ); document.write( "x=-3 and y=1/2\r \n" ); document.write( "\n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |