document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=501801>Question 501801</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Write a recursive rule for the sequence 36,18,9....\r<BR>\n" );
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document.write( "Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #338666 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=338666\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The recursive rule is \r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" src=\"http://latex.codecogs.com/gif.latex?\huge \dpi{150} a_{n} = \frac{a_{n-1}}{2}\" title=\"\huge \dpi{150} a_{n} = \frac{a_{n-1}}{2}\" />\r<BR>\n" );
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document.write( "Basically, to find the nth term <IMG STYLE=\"max-width:80%;\" src=\"http://latex.codecogs.com/gif.latex?\LARGE \inline \dpi{120} a_{n}\" title=\"\LARGE \inline \dpi{120} a_{n}\" />, you divide the previous term <IMG STYLE=\"max-width:80%;\" src=\"http://latex.codecogs.com/gif.latex?\LARGE \inline \dpi{120} a_{n-1}\" title=\"\LARGE \inline \dpi{120} a_{n-1}\" /> by 2 (ie you're cutting the previous term in half)\r<BR>\n" );
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document.write( "We can see this as 36 jumps to 18 (it cuts in half since 36/2 = 18) and similarly when 18 jumps to 9 (again, 18/2 = 9) </SPAN>\n" );
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