document.write( "Question 501736: calculate the area of a right triangle whose longest side is 17 and difference between its legs is 7 ? \n" ); document.write( "
Algebra.Com's Answer #338632 by mananth(16946)\"\" \"About 
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let one side be x
\n" ); document.write( "other side = x-7\r
\n" ); document.write( "\n" ); document.write( "x^2+(x-7)^2=17^2\r
\n" ); document.write( "\n" ); document.write( "x^2+x^2-14x+49=289
\n" ); document.write( "2x^2-14x+49-289=0
\n" ); document.write( "2x^2-14x-240=0
\n" ); document.write( "/2
\n" ); document.write( "x^2-7x-120=0
\n" ); document.write( "x^2-15x+7x-120=0
\n" ); document.write( "x(x-15)+7(x-15)=0
\n" ); document.write( "(x-15)(x+7)=0
\n" ); document.write( "x= 15 which is positive\r
\n" ); document.write( "\n" ); document.write( "other leg = 15-7 =8\r
\n" ); document.write( "\n" ); document.write( "Area = 1/2 * 8*15
\n" ); document.write( "Area = 60 sq. units
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