document.write( "Question 501684: a Carper lawyer wishes to determine the cost of carpeting a rectangle room who's perimeter is 32 feet. suppose that the length of the room is 4 more feet than its width. what is the length of the room and the total cost of the carpet if it cost $18.95 per square yard \n" ); document.write( "
Algebra.Com's Answer #338614 by nerdybill(7384)\"\" \"About 
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a Carper lawyer wishes to determine the cost of carpeting a rectangle room who's perimeter is 32 feet. suppose that the length of the room is 4 more feet than its width. what is the length of the room and the total cost of the carpet if it cost $18.95 per square yard
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\n" ); document.write( "Let w = width
\n" ); document.write( "then
\n" ); document.write( "w+4 = length
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\n" ); document.write( "2(w + w+4) = 32
\n" ); document.write( "2(2w+4) = 32
\n" ); document.write( "2w+4 = 16
\n" ); document.write( "2w = 12
\n" ); document.write( "w = 6 feet
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\n" ); document.write( "Length:
\n" ); document.write( "w+4 = 6+4 = 10 feet (length of room)
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\n" ); document.write( "area = 6*10 = 60 square feet
\n" ); document.write( "since there is 9square feet per square yard:
\n" ); document.write( "60/9 = 6.667 square yards
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\n" ); document.write( "Cost:
\n" ); document.write( "6.667 * 18.95 = $126.33
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