document.write( "Question 501687: the sum of the digits of a two digit number is 12, if the digits are reversed, the new number is 18 more than the original number. what is the original number? \n" ); document.write( "
Algebra.Com's Answer #338613 by mananth(16946)\"\" \"About 
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let x be in the tens place
\n" ); document.write( "y in the units place
\n" ); document.write( "the number will be (10x+y)\r
\n" ); document.write( "\n" ); document.write( "x+y =12 .....(1) The sum of the digits\r
\n" ); document.write( "\n" ); document.write( "10y+x=10x+y +18
\n" ); document.write( "9y-9x=18
\n" ); document.write( "/9
\n" ); document.write( "y-x=2... (2)\r
\n" ); document.write( "\n" ); document.write( "add (1) and (2)
\n" ); document.write( "2y=14
\n" ); document.write( "y=7
\n" ); document.write( "plug y in (1)
\n" ); document.write( "x=5
\n" ); document.write( "the number is 57
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