document.write( "Question 501621: Through (-2,3);Parallel to f(x)=x+2 \n" ); document.write( "
Algebra.Com's Answer #338606 by MathLover1(20849)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Parallel to \"f%28x%29=x%2B2\"\r
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Solved by pluggable solver: Finding the Equation of a Line Parallel or Perpendicular to a Given Line

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\n" ); document.write( " Since any two parallel lines have the same slope we know the slope of the unknown line is \"1\" (its from the slope of \"y=1%2Ax%2B2\" which is also \"1\").\n" ); document.write( "Also since the unknown line goes through (-2,3), we can find the equation by plugging in this info into the point-slope formula
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\n" ); document.write( " Point-Slope Formula:
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\n" ); document.write( " \"y-y%5B1%5D=m%28x-x%5B1%5D%29\" where m is the slope and (\"x%5B1%5D\",\"y%5B1%5D\") is the given point
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\n" ); document.write( " \"y-3=1%2A%28x%2B2%29\" Plug in \"m=1\", \"x%5B1%5D=-2\", and \"y%5B1%5D=3\"
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\n" ); document.write( " \"y-3=1%2Ax-%281%29%28-2%29\" Distribute \"1\"
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\n" ); document.write( " \"y-3=1%2Ax%2B2\" Multiply
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\n" ); document.write( " \"y=1%2Ax%2B2%2B3\"Add \"3\" to both sides to isolate y
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\n" ); document.write( " \"y=1%2Ax%2B5\" Combine like terms
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\n" ); document.write( " So the equation of the line that is parallel to \"y=1%2Ax%2B2\" and goes through (\"-2\",\"3\") is \"y=1%2Ax%2B5\"
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\n" ); document.write( " So here are the graphs of the equations \"y=1%2Ax%2B2\" and \"y=1%2Ax%2B5\"
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\n" ); document.write( " graph of the given equation \"y=1%2Ax%2B2\" (red) and graph of the line \"y=1%2Ax%2B5\"(green) that is parallel to the given graph and goes through (\"-2\",\"3\")
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