document.write( "Question 501665: please help me about this problem : one leg of a right triangle is 1 cm longer than the other leg, and the hypotenuse is 2 cm longer than the shorter leg. Find the lengths of the three sides of the triangle.I think the legs are 3 and 4 cm and the hypotenuse is 5 cm. but iam not sure about it, i need a solution and some explanation for this, i will also report this tomorrow on our class. please help me. thank you. \n" ); document.write( "
Algebra.Com's Answer #338604 by geetha_rama(94)![]() ![]() ![]() You can put this solution on YOUR website! Yes you are correct. \n" ); document.write( "Here's explanation: \n" ); document.write( "Let X be the length of shorter leg \n" ); document.write( " Y be the length of longer leg \n" ); document.write( " Z be the length of hypotensue.\r \n" ); document.write( "\n" ); document.write( "From the problem , we have \n" ); document.write( " Y = X + 1 ( longer leg is 1cm more than shorter leg) \n" ); document.write( " Z = X+ 2 (hypotenuse is 2cm longer than the shorter leg)\r \n" ); document.write( "\n" ); document.write( "We know that \n" ); document.write( " X^2 + Y^2 = Z^2\r \n" ); document.write( "\n" ); document.write( "Substituting values for Y and Z, \n" ); document.write( "X^2 + (X+1)^2 = (X+2)^2 \n" ); document.write( "X^2 + X^2 + 2*X + 1 = X^2 + 4*X + 4 \n" ); document.write( "X^2 -2*X -3 = 0 \n" ); document.write( "X^2 -3X + X - 3 = 0 \n" ); document.write( "X(X-3) + 1(X-3)= = \n" ); document.write( "(X-3)(X+1) = 0 \n" ); document.write( "X = 3, -1\r \n" ); document.write( "\n" ); document.write( "Length should be positive. \n" ); document.write( "Hence Shorter leg X = 3cm, Longer leg Y = 4cm and Hypotenuse Z = 5 cm \n" ); document.write( " |