document.write( "Question 501663: Sharon commutes to her office by train. When she walks to the train station,it takes her 40 min. When she rides her bike, it takes her 12 min. Her average walking rate is 7 mph less than her average biking rate. Find the distance from her house to the train station. \n" ); document.write( "
Algebra.Com's Answer #338603 by geetha_rama(94)\"\" \"About 
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Let d be the distance
\n" ); document.write( "X m/hr be the walking speed
\n" ); document.write( "Y m/hr be the speed in bike
\n" ); document.write( "X = Y -7 -> equation 1\r
\n" ); document.write( "\n" ); document.write( "distance = speed * time\r
\n" ); document.write( "\n" ); document.write( "Walking:
\n" ); document.write( " d = X*40/60 = 2*X/3\r
\n" ); document.write( "\n" ); document.write( "In Bike:
\n" ); document.write( " d = Y * 12/60 = Y/5\r
\n" ); document.write( "\n" ); document.write( "Equation above ,
\n" ); document.write( " 2*X/3 = Y/5\r
\n" ); document.write( "\n" ); document.write( "10X = 3Y\r
\n" ); document.write( "\n" ); document.write( "from equation 1,
\n" ); document.write( " 10(Y-7) = 3Y
\n" ); document.write( " 7Y = 70
\n" ); document.write( " Y = 10 miles/hr\r
\n" ); document.write( "\n" ); document.write( "Distance = 10*1/5 = 2 miles
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