document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=501597>Question 501597</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how many milimeters of a 15% acid solution and how many milimeters of 3% acid solution must be mixed to get 180 milimeters of a 10% acid solution </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #338595 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=338595\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> ---------percent	----------------			quantity							<BR>\n" );
document.write( "Acid I	15	----------------			x	ml						<BR>\n" );
document.write( "Acid II	3	----------------	120	-	x	ml						<BR>\n" );
document.write( "Mixture	10.00%	----------------	120									<BR>\n" );
document.write( "												<BR>\n" );
document.write( "15	x	+	3	(	120	-	x	)	=	10	*	120<BR>\n" );
document.write( "												<BR>\n" );
document.write( "15x+	360	-	3	x	=			1200		<BR>\n" );
document.write( "15	x	-	3	x	=	1200	-	360		<BR>\n" );
document.write( "12	x			=	840							<BR>\n" );
document.write( "/	12											<BR>\n" );
document.write( "	x=70	ml			15.00%		Acid I<BR>\n" );
document.write( "	50		ml			3.00%		Acid II<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );