document.write( "Question 501616: Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 60 mph. Train B is traveling at 64 mph. Train A passes a station at 1:15pm. If Train B passes the same station at 1:45 pm at what time will train B catch up to Train A? \n" ); document.write( "
Algebra.Com's Answer #338576 by geetha_rama(94)\"\" \"About 
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Speed of train A = 60mph
\n" ); document.write( "Speed of train B = 64mph\r
\n" ); document.write( "\n" ); document.write( "At 1:15PM Train A passes a station and train B passes the same station at 1:45PM.
\n" ); document.write( "Distance travelled by Train A from 1:15 pm to 1:45 pm = 60*1/2 = 30 miles.\r
\n" ); document.write( "\n" ); document.write( "Assume that it takes t hours from 1:45 PM for train B to catch train A
\n" ); document.write( "Let Distance travelled by train A in t hours = x miles - > equation 1
\n" ); document.write( "Distance that train B should travel in t hours = x+ 30 miles -> equation 2( since train A is already 30miles ahead of train B)\r
\n" ); document.write( "\n" ); document.write( "from equaion 1,
\n" ); document.write( " x = 60t
\n" ); document.write( "from equation 2,
\n" ); document.write( " x+30 = 64t\r
\n" ); document.write( "\n" ); document.write( "substituting value of x,
\n" ); document.write( " 60t+ 30 = 64t
\n" ); document.write( " 4t = 30
\n" ); document.write( "=> t = 7.5 \r
\n" ); document.write( "\n" ); document.write( "Train B will take 7 and a half hours to cross train B
\n" ); document.write( "At 9:15PM train B will cross train A (1:45 + 7:30)
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