document.write( "Question 501616: Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 60 mph. Train B is traveling at 64 mph. Train A passes a station at 1:15pm. If Train B passes the same station at 1:45 pm at what time will train B catch up to Train A? \n" ); document.write( "
Algebra.Com's Answer #338576 by geetha_rama(94)![]() ![]() ![]() You can put this solution on YOUR website! Speed of train A = 60mph \n" ); document.write( "Speed of train B = 64mph\r \n" ); document.write( "\n" ); document.write( "At 1:15PM Train A passes a station and train B passes the same station at 1:45PM. \n" ); document.write( "Distance travelled by Train A from 1:15 pm to 1:45 pm = 60*1/2 = 30 miles.\r \n" ); document.write( "\n" ); document.write( "Assume that it takes t hours from 1:45 PM for train B to catch train A \n" ); document.write( "Let Distance travelled by train A in t hours = x miles - > equation 1 \n" ); document.write( "Distance that train B should travel in t hours = x+ 30 miles -> equation 2( since train A is already 30miles ahead of train B)\r \n" ); document.write( "\n" ); document.write( "from equaion 1, \n" ); document.write( " x = 60t \n" ); document.write( "from equation 2, \n" ); document.write( " x+30 = 64t\r \n" ); document.write( "\n" ); document.write( "substituting value of x, \n" ); document.write( " 60t+ 30 = 64t \n" ); document.write( " 4t = 30 \n" ); document.write( "=> t = 7.5 \r \n" ); document.write( "\n" ); document.write( "Train B will take 7 and a half hours to cross train B \n" ); document.write( "At 9:15PM train B will cross train A (1:45 + 7:30) \n" ); document.write( " |