document.write( "Question 501440: A portion of $6,600 is invested at a 6 percent annual rate of interest, while the remainder is invested at a 4 percent rate. If the annual income from the two portions is the same, what dollar amount was invested at the 6 percent rate?
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document.write( "How can we solve the above question using algebraic equation ? Please help. thanks \n" );
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Algebra.Com's Answer #338532 by mananth(16946)![]() ![]() You can put this solution on YOUR website! 6%----------- x \n" ); document.write( "4%-----------6600-x\r \n" ); document.write( "\n" ); document.write( "0.04(6600-x)=0.06x \n" ); document.write( "264-0.04x=0.06x \n" ); document.write( "264 = 0.06x+0.04x \n" ); document.write( "264=0.10x \n" ); document.write( "x=264/0.1 \n" ); document.write( "x=2640 Investment @ 6% \n" ); document.write( " \n" ); document.write( " |