document.write( "Question 501226: Whats the equation for the line through (-2,4) parallel to the line through )1,1) and (5,7) \n" ); document.write( "
Algebra.Com's Answer #338470 by nerdybill(7384)\"\" \"About 
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Whats the equation for the line through (-2,4) parallel to the line through )1,1) and (5,7)
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\n" ); document.write( "Begin by finding slope of:
\n" ); document.write( "(1,1) and (5,7)
\n" ); document.write( "slope = (y2-y1)/(x2-x1)
\n" ); document.write( "slope = (7-1)/(5-1)
\n" ); document.write( "slope = 6/4
\n" ); document.write( "slope = 3/2
\n" ); document.write( "Since the new line is parallel, it must have the same slope of 3/2.
\n" ); document.write( "plug that and the given point (-2,4) into the \"point-slope\" form:
\n" ); document.write( "y - y1 = m(x - x1)
\n" ); document.write( "y - 4 = (3/2)(x - (-2))
\n" ); document.write( "y - 4 = (3/2)(x+2)
\n" ); document.write( "y - 4 = (3/2)x + 3
\n" ); document.write( "y = (3/2)x + 3 + 4
\n" ); document.write( "y = (3/2)x + 7 (this is what they're looking for, in \"slope-intercept\" form)\r
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