document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=500390>Question 500390</A>: <I><SPAN STYLE=\"word-break: break-all;\">  log3(x+12)-log3x=log3(x+9) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #338457 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=338457\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> log3(x+12)-log3x=log3(x+9)<BR>\n" );
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document.write( "log3(x+12)-log3(x)-log3(x+9)=0<BR>\n" );
document.write( "log3(x+12)-((log3(x)+log3(x+9))=0<BR>\n" );
document.write( "place under a single log<BR>\n" );
document.write( "log3[(x+12)/(x)(x+9)]=0<BR>\n" );
document.write( "Convert to exponential form: base(3) raised to log of number(0)=number[(x+12)/(x)(x+9)]<BR>\n" );
document.write( "3^0=[(x+12)/(x)(x+9)]=1<BR>\n" );
document.write( "x+12=x^2+9x<BR>\n" );
document.write( "x^2+8x-12=0<BR>\n" );
document.write( "let student solve for x using quadratic formula\r<BR>\n" );
document.write( "\n" );
document.write( "ans:<BR>\n" );
document.write( "x=-9.05 (reject, (x+9)>0)<BR>\n" );
document.write( "or<BR>\n" );
document.write( "x=1.29 </SPAN>\n" );
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