document.write( "Question 500234: in a ΔABC, angle B=38*. C is point in between B and D and there is a line drawn from A to C. AC=BC and AD=CD. what is angle D equal to?
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Algebra.Com's Answer #338455 by cleomenius(959)\"\" \"About 
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I'm not certain I understand the diagram,
\n" ); document.write( "It looks like you have a triangle ABC adjoining triangle ADC with the base on the bottom.
\n" ); document.write( "So, sides AC and BC are congruent, this is given, and angle b is given as 38 degrees.
\n" ); document.write( "Since BC and AC are congruent, angle BAC is congruent to ABC at 38 degrees.
\n" ); document.write( "38 degrees and 38 degrees = 76 degrees, 180 - 76 degrees = 104 degress. for angle BCA.
\n" ); document.write( "This makes angle ACD 76 degreees, since they are adjoining angles on a linear angle.
\n" ); document.write( "Since AD and CD are congruent, angle ACD and CAD are congruent at 76 degrees.
\n" ); document.write( "So CAD = 76 degrees and BAC = 38 degrees, so angle BAD = 114 degees,
\n" ); document.write( "BAD + 114, plus ABC = 38 = 152 degress.
\n" ); document.write( "180 - 152 = 28 degrees For angle C.
\n" ); document.write( "Cleomenius.
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