document.write( "Question 501109: 1. There is one x satisfying 5^(−3x−2)=1/78125. Use the rules of exponentiation and logarithms to find this number.\r
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document.write( "The value of x is...\r
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document.write( "2. There is one x satisfying log3(4x−8)=1. Use the rules of exponentiation and logarithms to find this number.\r
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document.write( "The value of x is... \n" );
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Algebra.Com's Answer #338439 by lwsshak3(11628) ![]() You can put this solution on YOUR website! 1. There is one x satisfying 5^(−3x−2)=1/78125. Use the rules of exponentiation and logarithms to find this number. \n" ); document.write( "The value of x is... \n" ); document.write( "2. There is one x satisfying log3(4x−8)=1. Use the rules of exponentiation and logarithms to find this number. \n" ); document.write( "The value of x is.. \n" ); document.write( "** \n" ); document.write( "1. 5^(−3x−2)=1/78125=78125^-1 \n" ); document.write( "Take log of both sides \n" ); document.write( "(-3x-2)log 5=(-1) log 78125 \n" ); document.write( "(-3x-2)/(-1)=- log 78125/log 5 \n" ); document.write( "3x+2=-7 \n" ); document.write( "3x=-9 \n" ); document.write( "x=-3 \n" ); document.write( "Check: \n" ); document.write( "5^(−3x−2)=5^-7=12.8*10^-6 \n" ); document.write( "1/78125=78125^-1=12.8*10^-6 \n" ); document.write( ".. \n" ); document.write( "2. log3(4x−8)=1 \n" ); document.write( "convert to exponential form: base(3) raised to log of number(1)=number(4x-8) \n" ); document.write( "3^1=4x-8 \n" ); document.write( "3=4x-8 \n" ); document.write( "4x=11 \n" ); document.write( "x=11/4 \n" ); document.write( "Check: \n" ); document.write( "log3(4x-8)=log(11-8)=log3(3)=1 (log of any base to its base=1) \n" ); document.write( " |