document.write( "Question 501008: Hi!\r
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document.write( "I am sorry if this kind of question has been asked often before, but I just couldnt figure out how to solve and I would be so thankful if anyone could tell how to solve this mathematically. Thanks so much in advance! \r
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document.write( "\"Through a combination of sight, sound, and smell a rabbit can detect a fox at 42 yards. When the rabbit detects the fox, it runs immediately straight to its hole. If the fox can run twice as fast as the rabbit, what is the maximum distance from its hole that a rabbit can safely venture? Assume that the rabbit escapes if they arrive at the hole at the same time.\"\r
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document.write( "Kind regards
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document.write( "Fube \n" );
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Algebra.Com's Answer #338425 by htmentor(1343)![]() ![]() You can put this solution on YOUR website! \"Through a combination of sight, sound, and smell a rabbit can detect a fox at 42 yards. When the rabbit detects the fox, it runs immediately straight to its hole. If the fox can run twice as fast as the rabbit, what is the maximum distance from its hole that a rabbit can safely venture? Assume that the rabbit escapes if they arrive at the hole at the same time.\" \n" ); document.write( "========================================================== \n" ); document.write( "Since the fox runs twice as fast, he can cover twice the distance in the same amount of time. If the rabbit and fox start out 42 yards apart, the fox can run 84 yards in the time it takes the rabbit to arrive at his hole. Therefore, the maximum safe distance is 84 - 42 = 42 yards. \n" ); document.write( " |