document.write( "Question 501066: marc goes to the store with exactly $1.00 in change. He has at least one of each coin less than a half-dollar coin, but does not have a half dollar coin. What is the most amount of coins he could have? What is the least amount of coins could he have?
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #338402 by htmentor(1343)![]() ![]() You can put this solution on YOUR website! marc goes to the store with exactly $1.00 in change. He has at least one of each coin less than a half-dollar coin, but does not have a half dollar coin. What is the most amount of coins he could have? What is the least amount of coins could he have? \n" ); document.write( "===================================== \n" ); document.write( "He has at least one penny, nickel, dime and quarter. If he has one quarter, one dime, one nickel and all the rest pennies, \n" ); document.write( "this would give him the most amount of coins. \n" ); document.write( "25 + 10 + 5 + p = 100 \n" ); document.write( "where p = the number of pennies \n" ); document.write( "This gives p = 60 \n" ); document.write( "So the most amount of coins = 63 \n" ); document.write( "For the least amount, we start with 3 quarters. That leaves 25 cents. Since we need at least one nickel and one penny, \n" ); document.write( "we can only use one dime. This leaves 15 cents. So we need two nickels and five pennies. \n" ); document.write( "So the least amount of coins = 3 + 1 + 2 + 5 = 11 \n" ); document.write( " |