document.write( "Question 501029: Mr. jenkins can dig a ditch in one hour less time than his son. working together they can do the job in 2/3 hrs. how long does it take mr. jenkins to do the job alone? \n" ); document.write( "
Algebra.Com's Answer #338394 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Mr. jenkins can dig a ditch in one hour less time than his son. \n" ); document.write( " working together they can do the job in 2/3 hrs. \n" ); document.write( " how long does it take mr. jenkins to do the job alone? \n" ); document.write( ": \n" ); document.write( "Let t = time for Mr. J to do the job alone \n" ); document.write( "Let the completed job = 1; (a dug ditch) \n" ); document.write( ": \n" ); document.write( "Let's do this in minutes \n" ); document.write( "2/3 hr = 40 min \n" ); document.write( "and \n" ); document.write( "(t+60) = time required by the son alone \n" ); document.write( "; \n" ); document.write( "A typical shared work equation \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Multiply by t(t+60); results \n" ); document.write( "40(t+60) + 40t = t(t+60) \n" ); document.write( ": \n" ); document.write( "40t + 2400 + 40t = t^2 + 60t \n" ); document.write( "80t + 2400 = t^2 + 60t \n" ); document.write( "Arrange as a quadratic equation \n" ); document.write( "t^2 + 60t - 80t - 2400 = 0 \n" ); document.write( "t^2 - 20t - 2400 = 0 \n" ); document.write( "factors to \n" ); document.write( "(t-60)(t+40) = 0 \n" ); document.write( "positive solution \n" ); document.write( "t = 60 min or 1 hr for Mr. J to do the job \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "you can check this in the original equation \n" ); document.write( " |