document.write( "Question 501029: Mr. jenkins can dig a ditch in one hour less time than his son. working together they can do the job in 2/3 hrs. how long does it take mr. jenkins to do the job alone? \n" ); document.write( "
Algebra.Com's Answer #338394 by ankor@dixie-net.com(22740)\"\" \"About 
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Mr. jenkins can dig a ditch in one hour less time than his son.
\n" ); document.write( " working together they can do the job in 2/3 hrs.
\n" ); document.write( " how long does it take mr. jenkins to do the job alone?
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\n" ); document.write( "Let t = time for Mr. J to do the job alone
\n" ); document.write( "Let the completed job = 1; (a dug ditch)
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\n" ); document.write( "Let's do this in minutes
\n" ); document.write( "2/3 hr = 40 min
\n" ); document.write( "and
\n" ); document.write( "(t+60) = time required by the son alone
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\n" ); document.write( "A typical shared work equation
\n" ); document.write( "\"40%2Ft\" + \"40%2F%28%28t%2B60%29%29\" = 1
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\n" ); document.write( "Multiply by t(t+60); results
\n" ); document.write( "40(t+60) + 40t = t(t+60)
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\n" ); document.write( "40t + 2400 + 40t = t^2 + 60t
\n" ); document.write( "80t + 2400 = t^2 + 60t
\n" ); document.write( "Arrange as a quadratic equation
\n" ); document.write( "t^2 + 60t - 80t - 2400 = 0
\n" ); document.write( "t^2 - 20t - 2400 = 0
\n" ); document.write( "factors to
\n" ); document.write( "(t-60)(t+40) = 0
\n" ); document.write( "positive solution
\n" ); document.write( "t = 60 min or 1 hr for Mr. J to do the job
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\n" ); document.write( ":
\n" ); document.write( "you can check this in the original equation
\n" ); document.write( "\"40%2F60\" + \"40%2F%28%2860%2B60%29%29\" =
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