document.write( "Question 501020: A mother is 20 years older then her daughter. Ten years ago the mother was twice as old as the daughter.how old are they now? \n" ); document.write( "
Algebra.Com's Answer #338384 by Maths68(1474)\"\" \"About 
You can put this solution on YOUR website!
Let
\n" ); document.write( "Present age of mother = m
\n" ); document.write( "Present age of daughter = d
\n" ); document.write( "Mother is 20 years older then her daughter means if we add 20 years to daughter's age both will be of equal age
\n" ); document.write( "m=d+20 .........(1)
\n" ); document.write( "Ten years ago means we have to subtract 10 from their present ages
\n" ); document.write( "m-10=d-10
\n" ); document.write( "then
\n" ); document.write( "the mother was twice as old as the daughter
\n" ); document.write( "m-10=2(d-10)
\n" ); document.write( "m-10=2d-20
\n" ); document.write( "m=2d-20+10
\n" ); document.write( "m=2d-10...........(2)
\n" ); document.write( "Plug in the value of m from (1) to (2)
\n" ); document.write( "m=2d-10
\n" ); document.write( "d+20=2d-10
\n" ); document.write( "d-2d=-10-20
\n" ); document.write( "-d=-30
\n" ); document.write( "Multiply by (-1) both sides of the equation
\n" ); document.write( "(-1)(-d)=(-1)(-30)
\n" ); document.write( "d=30
\n" ); document.write( "Now plug in the value of d in (1)
\n" ); document.write( "m=d+20 .........(1)
\n" ); document.write( "m=30+20
\n" ); document.write( "m=50\r
\n" ); document.write( "\n" ); document.write( "Mother is 50 and daughter is 30 years old\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );