document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=500992>Question 500992</A>: <I><SPAN STYLE=\"word-break: break-all;\"> When the sum of 8 and twice a positive number is subtracted from the square of the number, 0 results. find the number </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #338374 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=338374\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> When the sum of 8 and twice a positive number is subtracted from the square of the number, 0 results. find the number<BR>\n" );
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document.write( "Given: sum of 8 and twice a positive number [x] -> 8 + 2x<BR>\n" );
document.write( "Given: subtracted from the square of a number -> x^2 - (8 + 2x)<BR>\n" );
document.write( "Given: result is 0 -> x^2 - (8 + 2x) = 0<BR>\n" );
document.write( "x^2 - 2x - 8 = 0<BR>\n" );
document.write( "This can be factored as:<BR>\n" );
document.write( "(x-4)(x+2) = 0<BR>\n" );
document.write( "Take the positive solution:<BR>\n" );
document.write( "x = 4 </SPAN>\n" );
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