document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=500861>Question 500861</A>: <I><SPAN STYLE=\"word-break: break-all;\"> in a right angled triangle if one of the acute angle is twicethe other,prove that the hypotenuse is double the side opposite to smallest angle.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #338340 by </B><A HREF=/tutors/aboutme.mpl?userid=cleomenius><B>cleomenius(959)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=cleomenius><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=cleomenius><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=338340\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x + 2x  + 90 = 180<BR>\n" );
document.write( "3x = 90<BR>\n" );
document.write( "x = 30 degrees, the smallest angle.<BR>\n" );
document.write( "sin(30) = opp/hyp<BR>\n" );
document.write( "1/2 = x/hyp<BR>\n" );
document.write( "hyp = 2 * x.<BR>\n" );
document.write( "Cleomenius.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );