document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=500850>Question 500850</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A large rectangular movie screen in an Imax theater as an area of 10,384 square feet.  Find the dimensions of the screen if it is 30 feet longer than it is wide? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #338321 by </B><A HREF=/tutors/aboutme.mpl?userid=geetha_rama><B>geetha_rama(94)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=geetha_rama><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=338321\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x be the width of the screen and<BR>\n" );
document.write( "    x + 30 be the length of the screen<BR>\n" );
document.write( "Area of the screen = 10384 square feet<BR>\n" );
document.write( "=>x(x+30) = 10384<BR>\n" );
document.write( "x^2 + 30x = 10384<BR>\n" );
document.write( "x^2 + 30x - 10384 = 0<BR>\n" );
document.write( "x2+118x - 88x -10384 = 0<BR>\n" );
document.write( "x(x+118) -88(x+118) = 0<BR>\n" );
document.write( "(x+118)(x-88) = 0<BR>\n" );
document.write( "x=-118,88\r<BR>\n" );
document.write( "\n" );
document.write( "Since width should be positive,<BR>\n" );
document.write( "width = 88 feet<BR>\n" );
document.write( "length = 118 feet<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );