document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=500867>Question 500867</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If a supplementary angle is 20 more than 3 times the complent, then the measure of the angle is? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #338311 by </B><A HREF=/tutors/aboutme.mpl?userid=geetha_rama><B>geetha_rama(94)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=geetha_rama><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=338311\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x be the complementary angle and y be the supplementary angle.\r<BR>\n" );
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document.write( "y = 3x + 20   -> equation 1\r<BR>\n" );
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document.write( "sum of complementary and suppliemary angle is 180 degrees<BR>\n" );
document.write( "x+y=180\r<BR>\n" );
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document.write( "substituting equation 1 in the above,\r<BR>\n" );
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document.write( "x + 3x + 20 = 180<BR>\n" );
document.write( "4x = 160<BR>\n" );
document.write( "=>x = 40 degress<BR>\n" );
document.write( "  y = 3x + 20 = 120 + 20 = 140 degress\r<BR>\n" );
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document.write( "Copmplemenary angle = 40 degress <BR>\n" );
document.write( "Supplementary angle = 140 degrees </SPAN>\n" );
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