document.write( "Question 500868: Darrell has $2 less than five times as much money as Bob. Mary has as much money as Darrell ans Bob together. If all three of them together have $80, how much does Mary have? \n" ); document.write( "
Algebra.Com's Answer #338310 by geetha_rama(94)![]() ![]() ![]() You can put this solution on YOUR website! Let x be the amount that Darell have. y be the amount that Bob have and z be the amount that Mary have.\r \n" ); document.write( "\n" ); document.write( "x + y + z = 80 -> equation 1 (All three of them have $80 in total) \n" ); document.write( "x = 5y -2 -> equation 2 (Darell has $2 less than five times the money bob have) \n" ); document.write( "z= x+y -> equation 3 (Mary has sum of Darell and Bob's money)\r \n" ); document.write( "\n" ); document.write( "substituting equation 3 in equation 1, \n" ); document.write( "we have \n" ); document.write( " x + y + x+ y = 80 \n" ); document.write( "2x + 2y = 80\r \n" ); document.write( "\n" ); document.write( "=> x+y=40 \n" ); document.write( " x-5y = -2 ( from equation 2)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "subraticting above two equations, \n" ); document.write( " -6y = -42 \n" ); document.write( "=> y = 7 \n" ); document.write( " x = 5y -2 = 35 -2 = 33 \n" ); document.write( " Z = x+y = 40 \n" ); document.write( "Darell has $33, Bob has $7 and Mary has $40\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |