document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=500772>Question 500772</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The area of a triangular sheet of paper is 18 square inches. One side of the triangle is 14 inches more than two times the length of the altitude to that side. Find the length of that side and the altitude to that side. \r<BR>\n" );
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document.write( "I have looked at the examples on here and struggled even with their guidance as to where some of the numbers come from so far I have..\r<BR>\n" );
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document.write( "base=2a+14<BR>\n" );
document.write( "Altitude=a <BR>\n" );
document.write( "area= 18\r<BR>\n" );
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document.write( "so.. 2a+14= 18... so 2a=4.. I'm just very lost.<BR>\n" );
document.write( "Then I got 2x^2+14x-36=0 but when I tried to solve for it nothing was divisible by -18 that would equal 7 after you take a 2 out of the above question.. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #338273 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=338273\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> \"Then I got 2x^2+14x-36=0\" ___ 2(x - 2)(x + 9) = 0 </SPAN>\n" );
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