document.write( "Question 500673: how many liters of pure water should be mixed with a 3-L solution of 80% acid to produce a mixture that is 70% water? \n" ); document.write( "
Algebra.Com's Answer #338264 by ankor@dixie-net.com(22740)\"\" \"About 
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how many liters of pure water should be mixed with a 3-L solution of 80% acid to produce a mixture that is 70% water?
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\n" ); document.write( "Let w = amt of pure water required to accomplish this
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\n" ); document.write( "Write an amt of acid equation, acid amt remains the same, only the percent changes
\n" ); document.write( ".80(3) = .70(w+3)
\n" ); document.write( "2.4 = .7w + 2.1
\n" ); document.write( "2.4 - 2.1 = .7w
\n" ); document.write( ".3 = .7w
\n" ); document.write( "w = \".3%2F.7\"
\n" ); document.write( "w = .42857 liters of pure water
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