document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=500563>Question 500563</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A car and a bus set out at 2 pm from the same point, headed in the same direction. The average speed on the car is 30 mph slower than twice the speed of the bus. In 2 hours, the car is 20 miles ahead of the bus. Find the rate of the car.\r<BR>\n" );
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document.write( "I've know the rate of the car would be 2x-30, with x being the rate of the bus.<BR>\n" );
document.write( "I've used trial and error to see if I could figure it out, and I found that the bus was going 40 and the car 50.  After 2 hours, the car has gone 100 miles and the bus has gone 80 mles. But I can't figure out how to set it up and solve it with algebra! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #338181 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=338181\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> you have unknowns for the car and bus rates\r<BR>\n" );
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document.write( "d = r * t \r<BR>\n" );
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document.write( "\"In 2 hours, the car is 20 miles ahead of the bus\" ___ 2(2x - 30) = 2(x) + 20<BR>\n" );
document.write( "___ solve for the bus, then substitute to find the car </SPAN>\n" );
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