document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=500381>Question 500381</A>: <I><SPAN STYLE=\"word-break: break-all;\"> -3(2Y-1)=15 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #338131 by </B><A HREF=/tutors/aboutme.mpl?userid=stucke><B>stucke(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stucke><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=338131\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I got y=-2\r<BR>\n" );
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document.write( "--Foil (-3) to 2y & -1 to get -6y+3=15 ,subt. 3 from both sides -6y=12, then divide by -6. </SPAN>\n" );
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